163 lines
3.4 KiB
Plaintext
163 lines
3.4 KiB
Plaintext
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/*
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**********************************************************************
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*
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* CLP(R) Version 2.0 (Example Programs Release)
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* (C) Copyright, March 1986, Monash University
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*
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**********************************************************************
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*/
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%
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% Algebraic combinations of options: see [Lassez, McAloon & Yap].
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%
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% Note that buy and sell are the negation of each other
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% heaviside function
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h(X,Y,Z) :- Y < X , Z = 0.
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h(X,Y,Z) :- Y >= X, Z = 1.
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% ramp function
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r(X,Y,Z) :- Y < X , Z = 0.
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r(X,Y,Z) :- Y >= X, Z = Y - X.
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% option valuation
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% Variables are as previously described
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value(Type,Buy_or_Sell,S,C,P,I,X,B,Value) :-
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check_param(S,C,P,I,X,B),
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get_sign(Buy_or_Sell,Sign),
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lookup_option(Type,S,C,P,I,X,B,
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B1,B2,H1,H2,R1,R2),
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h(B1,S,T1),h(B2,S,T2),r(B1,S,T3),r(B2,S,T4),
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Value = Sign*(H1*T1 + H2*T2 + R1*T3 + R2*T4).
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% safety check
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check_param(S,C,P,I,X,B) :-
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S >= 0, C >= 0, P >= 0,
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I >= 0, X >= 0, B >= 0 .
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% Buy or sell are just opposite
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get_sign(buy,-1).
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get_sign(sell,1).
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% lookup option vector
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lookup_option(Type,S,C,P,I,X,B,B1,B2,H1,H2,R1,R2) :-
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table(Type,S,C,P,I,X,B,B1,B2,H1,H2,R1,R2).
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% Table of values for B1,B2,H1,H2,R1,R2
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% generic format - lookup_table(Type,Pos_neg,S,C,P,I,X,B,B1,B2,H1,H2,R1,R2).
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% where K to R21 are obtained from the table
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% M is a multiplier which is -1 or 1 depending on whether one
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% is buying or selling the option
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table( stock, S, C, P, I, X, B, 0, 0, S*(1+I), 0, -1, 0).
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table( call, S, C, P, I, X, B, 0, X, C*(1+I), 0, 0, -1).
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table( put, S, C, P, I, X, B, 0, X, P*(1+I)-X, 0, 1, -1).
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table( bond, S, C, P, I, X, B, 0, 0, B*(1+I), 0, 0, 0).
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% A straightforward query is finding the
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% value of selling a call option where
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% the call price is 5, exercise price 50,
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% interest rate 5% and current stock price 60.
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% Note that this query assigns variables just
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% to make the query look more readable
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go1(Value) :-
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Call=5,Exercise=50,Interest=0.05,Stock=60 ,
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value(call,sell,Stock,Call,_,Interest,Exercise,_,Value).
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% Answer:
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% W = -4.75
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% If we just the the question upside down and
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% ask what should the stock price be in order that
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% my wealth is more than 5. Then we have
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go2(Stock,W) :-
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Call=5,Exercise=50,Interest=0.05 ,
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W > 5,
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value(call,sell,Stock,Call,_,Interest,Exercise,_,W).
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% Answer 1:
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% W = 5.25
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% 50 > S
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% S >= 0
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% Answer 2:
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% W = 55.25 - S
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% 50.25 > S
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% S >= 50
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% straddle
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% The general query is
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% ?- Wealth=W1+W2,....
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% value(call,buy,S,C,_,I,X,_,W1),
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% value(put,buy,S,_,P,I,X,_,W2).
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go3(Stock,W) :-
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Call=5,Int=0.05,X=50,Put=7,
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W >= 10,
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value(put,buy,Stock,_,Put,Int,X,_,W1),
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value(call,buy,Stock,Call,_,Int,X,_,W2),
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W=W1+W2.
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% Answer 1:
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% S = 37.4 - W
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% W >= 10
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% S >= 0
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% Answer 2:
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% S = 62.6 + W
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% W >= 10
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% S >= 0
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go4(S,W) :-
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I=0.1,P1=10,X1=20,
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value(put,sell,S,_,P1,I,X1,_,W1),
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P2=18,X2=40,
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value(put,buy,S,_,P2,I,X2,_,W2),
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C3=15,X3=60,
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value(call,buy,S,C3,_,I,X3,_,W3),
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C4=10,X4=80,
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value(call,sell,S,C4,_,I,X4,_,W4),
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W=W1+W2+W3+W4.
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% Answer 1:
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% W = 5.7
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% 20 > S
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% S >= 0
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% Answer 2:
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% S = 25.7 - W
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% 5.7 >= W
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% 14.3 + W > 0
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% S >= 0
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% Answer 3:
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% W = -14.3
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% S >= 40
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% 60 > S
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% Answer 4:
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% S = 74.3 + W
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% 14.3 + W >= 0
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% 5.7 > W
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% S >= 0
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% Answer 5:
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% W = 5.7
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% S >= 80
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go5(S,W) :-
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Put=5,Exercise=20,Interest=0.1,
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S >= 0,
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W > 100,
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value(put,buy,S,_,Put,Interest,Exercise,_,W).
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% No solution.
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?- printf("\n>>> Sample goals (some with multiple answers):\n", []),
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printf(" go1(W), go2(S, W), go3(S, W), go4(S, W), go5(S, W)\n", []).
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