77 lines
1.6 KiB
Plaintext
77 lines
1.6 KiB
Plaintext
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:- object(enigma).
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:- info([
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version is 1.0,
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author is 'Paulo Moura',
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date is 2006/01/22,
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comment is 'Example of using DCG rules to decrypt a enigma where words are made of numbers corresponding to the characters on a cellphone keypad.']).
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:- public(solve/2).
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:- mode(solve(+string, -list(atom)), zero_or_one).
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:- info(solve/2, [
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comment is 'Solves a cellphone enigma against a dictionary of words.',
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argnames is ['Enigma', 'Message']]).
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solve(Enigma, Message) :-
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phrase(message(Message), Enigma).
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message([Word| Words]) --> separator, word(Chars), {atom_chars(Word, Chars), dictionary(Word)}, !, message(Words).
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message([]) --> separator.
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word([Char| Chars]) --> character(Char), word(Chars).
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word([]) --> [].
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separator --> " ", !, separator.
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separator --> [].
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character(a) --> "2".
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character(b) --> "2".
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character(c) --> "2".
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character(d) --> "3".
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character(e) --> "3".
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character(f) --> "3".
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character(g) --> "4".
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character(h) --> "4".
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character(i) --> "4".
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character(j) --> "5".
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character(k) --> "5".
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character(l) --> "5".
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character(m) --> "6".
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character(n) --> "6".
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character(o) --> "6".
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character(p) --> "7".
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character(q) --> "7".
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character(r) --> "7".
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character(s) --> "7".
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character(t) --> "8".
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character(u) --> "8".
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character(v) --> "8".
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character(w) --> "9".
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character(x) --> "9".
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character(y) --> "9".
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character(z) --> "9".
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dictionary(dinner).
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dictionary(have).
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dictionary(i).
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dictionary(love).
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dictionary(miss).
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dictionary(much).
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dictionary(me).
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dictionary(you).
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dictionary(so).
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dictionary(to).
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dictionary(tonight).
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dictionary(with).
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dictionary(would).
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:- end_object.
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