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			445 lines
		
	
	
		
			11 KiB
		
	
	
	
		
			Plaintext
		
	
	
	
	
	
			
		
		
	
	
			445 lines
		
	
	
		
			11 KiB
		
	
	
	
		
			Plaintext
		
	
	
	
	
	
| % Boolean tests from Daniel Diaz
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| % 931127 adapted to Eclipse and CHRs by Thom Fruehwirth, ECRC
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| 
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| %From diaz@margaux.inria.fr Tue Nov 23 18:59:17 1993 
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| %
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| %I send you 3 programs schur.pl, pigeon.pl and queens.pl and a file
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| %b_bips.pl containing the necessary built-ins and libraries.
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| 
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| 
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| 
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| 
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| %---schur.pl---
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| 
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| /*-------------------------------------------------------------------------*/
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| /* Benchmark (Boolean)                  INRIA Rocquencourt - ChLoE Project */
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| /*                                                                         */
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| /* Name           : bschur.pl                                              */
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| /* Title          : Schur's lemma                                          */
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| /* Original Source: Giovanna Dore - Italy                                  */
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| /* Adapted by     : Daniel Diaz - INRIA France                             */
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| /* Date           : January 1993                                           */
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| /*                                                                         */
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| /* Color the integers 1,2...,N with 3 colors so that there is no monochrome*/
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| /* triplets (x,y,z) where x+y=z. Solution iff N<=13.                       */
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| /* The solution is a list [ [Int11,Int12,Int13],..., [IntN1,IntN2,IntN3] ] */
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| /* where Intij is 1 if the integer i is colored with the color j.          */
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| /*                                                                         */
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| /* Solution:                                                               */
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| /* N=4  [[0,0,1],[0,1,0],[0,0,1],[1,0,0]]                                  */
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| /*      [[0,0,1],[0,1,0],[0,1,0],[0,0,1]]                                  */
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| /*        ...                                                              */
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| /* N=13 [[0,0,1],[0,1,0],[0,1,0],[0,0,1],[1,0,0],[1,0,0],[0,0,1],[1,0,0],  */
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| /*       [1,0,0],[0,0,1],[0,1,0],[0,1,0],[0,0,1]] (first solution)         */
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| /*-------------------------------------------------------------------------*/
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| 
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| bschur:-	write('N ?'), read(N),
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| 	cputime( Starttime),
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| 	(schur(N,A),
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| %	 write(A), nl, 
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| 	 fail 
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| 	   ;
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| 	 write('No more solutions'), nl),
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| 	cputime( Cputime),
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| 	Y is Cputime-Starttime,
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| 	write('time : '), write(Y), nl.
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| 
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| cputime( Ts) :- 
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| 	statistics( runtime, [Tm,_]),
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| 	Ts is Tm/1000.
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| 
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| 
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| schur(N,A):-
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| 	create_array(N,3,A),
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| 	for_each_line(A,only1),
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| 	pair_constraints(A,A),
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| 	!,
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| %	labeling.
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| 	array_labeling(A).
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| 
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| 
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| 
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| 
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| pair_constraints([],_):-
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| 	!.
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| 
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| pair_constraints([_],_):-
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| 	!.
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| 
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| pair_constraints([_,[K1,K2,K3]|A2],[[I1,I2,I3]|A1]):-
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| 	and0(I1,K1),
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| 	and0(I2,K2),
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| 	and0(I3,K3),
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| 	triplet_constraints(A2,A1,[I1,I2,I3]),
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| 	pair_constraints(A2,A1).
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| 
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| 
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| 
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| 
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| triplet_constraints([],_,_).
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| 
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| triplet_constraints([[K1,K2,K3]|A2],[[J1,J2,J3]|A1],[I1,I2,I3]):-
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| 	and0(I1,J1,K1),
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| 	and0(I2,J2,K2),
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| 	and0(I3,J3,K3),
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| 	triplet_constraints(A2,A1,[I1,I2,I3]).
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| 
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| 
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| 
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| 
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| 
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| 
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| %--- pigeon.pl ---
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| 
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| /*-------------------------------------------------------------------------*/
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| /* Benchmark (Boolean)                  INRIA Rocquencourt - ChLoE Project */
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| /*                                                                         */
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| /* Name           : bpigeon.pl                                             */
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| /* Title          : pigeon-hole problem                                    */
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| /* Originated from:                                                        */
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| /* Adapted by     : Daniel Diaz - INRIA France                             */
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| /* Date           : January 1993                                           */
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| /*                                                                         */
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| /* Put N pigeons in M pigeon-holes. Solution iff N<=M.                     */
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| /* The solution is a list [ [Pig11,...,Pig1m], ... ,[Pign1,...,Pignm] ]    */
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| /* where Pigij = 1 if the pigeon i is in the pigeon-hole j                 */
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| /*                                                                         */
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| /* Solution:                                                               */
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| /* N=2 M=3 [[0,0,1],[0,1,0]]                                               */
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| /*         [[0,0,1],[1,0,0]]                                               */
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| /*         [[0,1,0],[0,0,1]]                                               */
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| /*         [[0,1,0],[1,0,0]]                                               */
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| /*         [[1,0,0],[0,0,1]]                                               */
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| /*         [[1,0,0],[0,1,0]]                                               */
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| /*-------------------------------------------------------------------------*/
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| 
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| 
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| bpigeon:-	write('N ?'), read(N), write('M ?'), read(M),
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| 	cputime( Starttime),
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| 	(bpigeon(N,M,A), 
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| %	 write(A), nl, 
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| 	 fail 
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| 	   ;
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| 	 write('No more solutions'), nl),
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| 	cputime( Cputime),
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| 	Y is Cputime-Starttime,
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| 	write('time : '), write(Y), nl.
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| 
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| 
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| 
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| 
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| bpigeon(N,M,A):-
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| 	create_array(N,M,A),
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| 	for_each_line(A,only1),
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| 	for_each_column(A,atmost1),
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| 	!,
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| 	array_labeling(A).
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| 
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| 
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| 
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| 
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| 
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| 
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| 
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| 
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| 
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| %--- queens.pl ---
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| 
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| /*-------------------------------------------------------------------------*/
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| /* Benchmark (Boolean)                  INRIA Rocquencourt - ChLoE Project */
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| /*                                                                         */
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| /* Name           : bqueens.pl                                             */
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| /* Title          : N-queens problem                                       */
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| /* Original Source: Daniel Diaz - INRIA France                             */
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| /* Adapted by     :                                                        */
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| /* Date           : January 1993                                           */
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| /*                                                                         */
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| /* Put N queens on an NxN chessboard so that there is no couple of queens  */
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| /* threatening each other.                                                 */
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| /* The solution is a list [ [Que11,...,Que1N], ... ,[QueN1,...,QueNN] ]    */
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| /* where Queij is 1 if the the  is a queen on the ith line an jth row.     */
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| /*                                                                         */
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| /* Solution:                                                               */
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| /* N=4  [[0,0,1,0],         [[0,1,0,0],                                    */
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| /*       [1,0,0,0],          [0,0,0,1],                                    */
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| /*       [0,0,0,1],  and     [1,0,0,0],                                    */
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| /*       [0,1,0,0]]          [0,0,1,0]]                                    */
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| /*                                                                         */
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| /* N=8  [[0,0,0,0,0,0,0,1], (first solution)                               */
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| /*       [0,0,0,1,0,0,0,0],                                                */
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| /*       [1,0,0,0,0,0,0,0],                                                */
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| /*       [0,0,1,0,0,0,0,0],                                                */
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| /*       [0,0,0,0,0,1,0,0],                                                */
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| /*       [0,1,0,0,0,0,0,0],                                                */
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| /*       [0,0,0,0,0,0,1,0],                                                */
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| /*       [0,0,0,0,1,0,0,0]]                                                */
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| /*-------------------------------------------------------------------------*/
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| 
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| 
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| bqueens:-	write('N ?'), read(N),
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| 	cputime( Starttime),
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| 	(bqueens(N,A), 
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| %        write(A), nl,
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| 	 fail
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| 	   ; 
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| 	 write('No more solutions'), nl),
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| 	cputime( Cputime),
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| 	Y is Cputime-Starttime,
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| 	write('time : '), write(Y), nl.
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| 
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| 
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| 
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| 
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| bqueens(N,A):-
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| 	create_array(N,N,A),
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| 	for_each_line(A,only1),
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| 	for_each_column(A,only1),
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| 	for_each_diagonal(A,N,N,atmost1),
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| 	!,
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| 	array_labeling(A).
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| 
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| 
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| 
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| 
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| 
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| 
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| 
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| 
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| %--- b_bips.pl ---
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| 
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| 
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| 
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| %I also use the following shorthands:
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| 
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| and0(X,Y):-
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| 	and(X,Y,0).
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| %	delay([X,Y],and(X,Y,0)).
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| 
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| 
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| 
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| or1(X,Y):-
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| 	or(X,Y,1).
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| 
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| 
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| and0(X,Y,Z):-
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| 	and(X,Y,XY),
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| 	and(XY,Z,0).
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| %	delay([X,Y,Z],(
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| %	and(X,Y,XY),
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| %	and(XY,Z,0))).
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| 
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| 
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| 
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| 
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| or1(X,Y,Z):-
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| 	or(X,Y,XY),
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| 	or(XY,Z,1).
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| 
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| 
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| /*-------------------------------------------------------------------------*/
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| /* Prolog to Wam Compiler               INRIA Rocquencourt - ChLoE Project */
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| /* Version 1.0  -  C Run-time                           Daniel Diaz - 1991 */
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| /* Extended to FD Constraints (July 1992)                                  */
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| /*                                                                         */
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| /* Built-In: B predicates (booleans)                                       */
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| /*                                                                         */
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| /* b_bips.pl                                                               */
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| /*-------------------------------------------------------------------------*/
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| 
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| 	/* Symbolic constraints */
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| 
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| %:- public only_one/1, at_least_one/1, at_most_one/1.
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| 
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| %only_one(L):- card(1,1,L).
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| %at_most_one(L):- card(0,1,L).
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| 
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| 
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| only_one(L):-
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| 	at_least_one(L),
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| 	at_most_one(L).
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| 
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| 
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| 
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| 
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| at_least_one(L):- 
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| 	at_least_one1(L,1).
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| 
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| 
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| at_least_one1([X],X).
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| 
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| at_least_one1([X|L],R):- 
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| 	at_least_one1(L,R1),
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| 	or(X,R1,R).
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| 
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| 
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| 
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| 
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| at_most_one([]).
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| 
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| at_most_one([X|L]):-
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| 	not_two(L,X),
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| 	at_most_one(L).
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| 
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| 
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| 
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| 
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| not_two([],_).
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| 
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| not_two([X1|L],X):- 
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| 	and0(X1,X),
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| 	not_two(L,X).
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| 
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| 
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| 
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| 	/* Array procedures */
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| 
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| %:- public create_array/3, for_each_line/2, for_each_column/2, for_each_diagonal/4, array_labeling/1.
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| 
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| 
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| 	/*---------------------------------------------------------*/
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| 	/*                                                         */
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| 	/* An array NL x NC elements is represented as follows :   */
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| 	/* A = [L_1, ..., L_NL] with L_i = [X_i_1, ..., X_i_NC]    */
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| 	/* Hence :                                                 */
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| 	/* A = [ [X_1_1,..., X_1_NC], ..., [X_NL_1,..., X_NL_NC] ] */
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| 	/*---------------------------------------------------------*/
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| 
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| 	% create_array(NL,NC,A)
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| 	%     NL: nb of lines   NC:nb of columns   A:array
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| 	%     creates an array (with unbound variables)
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|  
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| create_array(NL,NC,A):-
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| 	create_array1(0,NL,NC,A),
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| 	!.
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| 
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| 
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| create_array1(NL,NL,_,[]).
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| 
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| create_array1(I,NL,NC,[L|A]):-
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| 	create_one_line(0,NC,L),
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| 	I1 is I+1,
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| 	create_array1(I1,NL,NC,A).
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| 
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| 
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| 
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| 
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| create_one_line(NC,NC,[]).
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| 
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| create_one_line(J,NC,[_|L]):-
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| 	J1 is J+1,
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| 	create_one_line(J1,NC,L).
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| 
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| 
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| 
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| 
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| 	% for_each_line(A,P)
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| 	%     A:array   P: program atom
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| 	%     calls: array_prog(P,L) for each line L (L is a list)
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|  
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| for_each_line([],_).
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| 
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| for_each_line([L|A],P):-
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| 	array_prog(P,L),
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| 	for_each_line(A,P).
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| 
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| 
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| 
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| 
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| 	% for_each_column(A,P)
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| 	%     A:array   P: program atom
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| 	%     calls:  array_prog(P,L) for each column L (L is a list)
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|  
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| for_each_column([[]|_],_):-
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| 	!.
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| 
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| for_each_column(A,P):-
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| 	create_column(A,C,A1),
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| 	array_prog(P,C),
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| 	for_each_column(A1,P).
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| 
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| 
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| 
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| 
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| create_column([],[],[]).
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| 
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| create_column([[X|L]|A],[X|C],[L|A1]):-
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| 	create_column(A,C,A1).
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| 
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| 
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| 
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| 
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| 	% for_each_diagonal(A,NL,NC,P)
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| 	%     A:array   NL: nb of lines   
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| 	%     NC:nb of columns   P: program atom
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| 	%     calls:  array_prog(P,L) for each diagonal D (D is a list)
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|  
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| for_each_diagonal(A,NL,NC,P):-
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| 	NbDiag is 2*(NL+NC-1),              % numbered from 0 to NbDiag-1
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| 	create_lst_diagonal(0,NbDiag,LD),
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| 	fill_lst_diagonal(A,0,NL,NC,LD,LD1),
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| 	!,
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| 	for_each_line(LD1,P).
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| 
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| 
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| 
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| 
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| create_lst_diagonal(NbDiag,NbDiag,[]).
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| 
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| create_lst_diagonal(I,NbDiag,[[]|LD]):-
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| 	I1 is I+1,
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| 	create_lst_diagonal(I1,NbDiag,LD).
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| 
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| 
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| 
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| 
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| fill_lst_diagonal([],_,_,_,LD,LD).
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| 
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| fill_lst_diagonal([L|A],I,NL,NC,LD,LD2):-
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| 	I1 is I+1,
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| 	fill_lst_diagonal(A,I1,NL,NC,LD,LD1),
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| 	one_list(L,I,NL,0,NC,LD1,LD2).
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| 
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| 
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| 
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| 
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| 
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| one_list([],_,_,_,_,LD,LD).
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| 
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| one_list([X|L],I,NL,J,NC,LD,LD3):-
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| 	J1 is J+1,
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| 	one_list(L,I,NL,J1,NC,LD,LD1),
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| 	NoDiag1 is I+J,
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| 	NoDiag2 is I+NC-J+NL+NC-2,
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| 	add_in_lst_diagonal(0,NoDiag1,X,LD1,LD2),
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| 	add_in_lst_diagonal(0,NoDiag2,X,LD2,LD3).
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| 
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| 
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| 
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| 
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| 
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| add_in_lst_diagonal(NoDiag,NoDiag,X,[D|LD],[[X|D]|LD]).
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| 
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| add_in_lst_diagonal(K,NoDiag,X,[D|LD],[D|LD1]):-
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| 	K1 is K+1,
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| 	add_in_lst_diagonal(K1,NoDiag,X,LD,LD1).
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| 
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| 
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| 
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| array_prog(only1,L):- !,
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| 	only_one(L).
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| 
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| array_prog(atmost1,L):- !,
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| 	at_most_one(L).
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| 
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| 
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| 
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| 
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| array_labeling([]).
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| 
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| array_labeling([L|A]):-
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| 	label_bool(L),
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| 	array_labeling(A).
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| 
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| 
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| %--- end ---
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