62 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Prolog
		
	
	
	
	
	
			
		
		
	
	
			62 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Prolog
		
	
	
	
	
	
| 
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| abi_table(
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| /* h */ [ 0.50,
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| /* m */   0.40,
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| /* l */   0.10 ]).
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| 
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| abi_table(_, T) :- abi_table(T).
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| 
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| pop_table(
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| /*        h     m    l */
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| /* h */ [ 0.9,  0.2, 0.01,
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| /* m */   0.09, 0.6, 0.09,
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| /* l */   0.01, 0.2, 0.9  ]).
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| 
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| pop_table(_, T) :- pop_table(T). 
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| 
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| diff_table(
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| /* h */ [ 0.25,
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| /* m */   0.50,
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| /* l */   0.25 ]).
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| 
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| dif_table(_, T) :- diff_table(T). 
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| 
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| int_table(
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| /* h */ [ 0.5,
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| /* m */   0.4,
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| /* l */   0.1 ]).
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| 
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| int_table(_,T ,[h,m,l]) :- int_table(T).
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| 
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| grade_table(
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| /*        h h   h m   h l   m h  m m   m l   l h   l m   l l */
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| /* a */ [ 0.2,  0.7,  0.85, 0.1, 0.2,  0.5,  0.01, 0.05, 0.1,
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| /* b */   0.6,  0.25, 0.12, 0.3, 0.6,  0.35, 0.04, 0.15, 0.4,
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| /* c */   0.15, 0.04, 0.02, 0.4, 0.15, 0.12, 0.5,  0.6,  0.4,
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| /* d */   0.05, 0.01, 0.01, 0.2, 0.05, 0.03, 0.45, 0.2,  0.1 ]).
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| 
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| grade_table(I, D, 
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| 	p([a,b,c,d], T, [I,D])) :- grade_table(T).
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|     
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| sat_table(
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| /*        h a   h b   h c   h d  m a   m b  m c  m d   l a   l b  l c   l d */
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| /* h */ [ 0.98, 0.9,  0.8 , 0.6, 0.9,  0.4, 0.2, 0.01, 0.5,  0.2, 0.01, 0.01,
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| /* m */   0.01, 0.09, 0.15, 0.3, 0.05, 0.4, 0.3, 0.04, 0.35, 0.3, 0.09, 0.01,
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| /* l */   0.01, 0.01, 0.05, 0.1, 0.05, 0.2, 0.5, 0.95, 0.15, 0.5, 0.9,  0.98 ]).
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| 
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| satisfaction_table(A, G, p([h,m,l], T, [A,G])) :- sat_table(T).
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| 
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| 
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| % The idea is quite simple:
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| %  hs = h -> r = ( 0.9, 0.1, 0)
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| %  hs = m -> r = ( 0.2, 0.6, 0.2)
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| %  hs = l -> r = ( 0, 0.1, 0.9)
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| %
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| % add all and divide on the number of elements on the table!
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| %
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| rating_prob_table(
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|   [ 0.9,  0.05, 0.01,
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|     0.09, 0.9,  0.09,
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|     0.01, 0.05, 0.9  ]).
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| 
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